Solve y' + 2y = e^{−x}, with y(0)=0. Which is y(x)?

Solve y' + 2y = e^{−x}, with y(0)=0. Which is y(x)?

• A. y = (1/2) e^{2x} − (1/2) e^{−x}
• B. y = (1/3) e^{2x} − (1/3) e^{−x}
• C. y = −(1/3) e^{2x} + (1/3) e^{−x}
• D. y = (1/3) e^{2x} + (1/3) e^{−x}

Answer: (B)