Which statement about non-real roots for polynomials with real coefficients is true?

Boost your skills in A Level Further Mathematics Core Pure. Study with flashcards and multiple choice questions, each question is followed by hints and explanations. Get prepared for your exam with confidence!

Multiple Choice

Which statement about non-real roots for polynomials with real coefficients is true?

Explanation:
When a polynomial has real coefficients, complex roots come in conjugate pairs. If a + bi (with b ≠ 0) is a root, then the conjugate a − bi is also a root. This happens because the polynomial with real coefficients satisfies P(z) = sum real_coef_k z^k, so taking complex conjugates gives P(a − bi) = overline(P(a + bi)) = 0 whenever P(a + bi) = 0. This pairing explains why non-real roots never occur alone or in triples: they always appear together as a conjugate pair. The quadratic factor x^2 − 2ax + (a^2 + b^2) corresponds to such a pair and has real coefficients, reinforcing why these roots must come in pairs.

When a polynomial has real coefficients, complex roots come in conjugate pairs. If a + bi (with b ≠ 0) is a root, then the conjugate a − bi is also a root. This happens because the polynomial with real coefficients satisfies P(z) = sum real_coef_k z^k, so taking complex conjugates gives P(a − bi) = overline(P(a + bi)) = 0 whenever P(a + bi) = 0. This pairing explains why non-real roots never occur alone or in triples: they always appear together as a conjugate pair. The quadratic factor x^2 − 2ax + (a^2 + b^2) corresponds to such a pair and has real coefficients, reinforcing why these roots must come in pairs.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy